Chip Salzenberg on 26 Apr 2004 22:46:04 -0000 |
According to Walt Mankowski: > printf("v has %d elements\n", v.size()); > > Looking through the STL documentation as well as the header files, it > appears that size() returns a size_type, and size_type is really a > size_t. Is size_t guaranteed to be a long? I should point out that if you're writing truly generic code designed to handle any vector<>, you can't assume that type type of v.size() is size_t, because that type is determined by the third template parameter, the "allocator"; some user may use a non-standard allocator which means the return type of v.size() may be different. C++ is such a pain in the ass sometimes. -- Chip Salzenberg - a.k.a. - <chip@pobox.com> "I wanted to play hopscotch with the impenetrable mystery of existence, but he stepped in a wormhole and had to go in early." // MST3K ___________________________________________________________________________ Philadelphia Linux Users Group -- http://www.phillylinux.org Announcements - http://lists.phillylinux.org/mailman/listinfo/plug-announce General Discussion -- http://lists.phillylinux.org/mailman/listinfo/plug
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