Dan Crosta on 19 May 2005 18:04:32 -0000

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Re: [PLUG] bash, double for

Jeff Abrahamson wrote:

I want to do the following in bash.  I don't see an easy way.  (I see
very complicated ways.)  Anyone see an easy way?

for((n=0; n<10; n++)) and $array; do echo Element $n of array is $array[$n]

There's always:

for val in $array; do
   echo Element $n of array is $val
   n=`echo "$n + 1" | bc`

There's also probably a better way to increment $n, but this is the pattern I found first, so I use it.

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