Re: [PLUG] bash, double for

[Dan Crosta <dcrosta@sccs.swarthmore.edu>]

Jeff Abrahamson wrote:

> I want to do the following in bash.  I don't see an easy way.  (I see
> very complicated ways.)  Anyone see an easy way?
>
>    for((n=0; n<10; n++)) and $array; do 
>        echo Element $n of array is $array[$n]
>    done
>
>  
There's always:

n=0
for val in $array; do
   echo Element $n of array is $val
   n=`echo "$n + 1" | bc`
done

There's also probably a better way to increment $n, but this is the 
pattern I found first, so I use it.

dsc
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