Re: [PLUG] correct way to do this in bash

[jharlow1@gmail.com]

Assuming you don't need to restart the process but just need to roll the file at 8, 
You could write a bash script that traps a signal, and in the trap, redirect the stdout and stderr (using exec)  to a new file (with date/time stamp) or some such

Instead of restarting the process at 8am just send the signal to the script (SIGUSR1 or some such) 
------Original Message------
From: Mag Gam
Sender: plug-bounces@lists.phillylinux.org
To: Philadelphia Linux User's Group Discussion List
ReplyTo: Philadelphia Linux User's Group Discussion List
Sent: Sep 22, 2009 6:19 PM
Subject: [PLUG] correct way to do this in bash

Currently for my research I have a process that writes 24 hours and 5
days a week.  Its writes to standard out and there is standard error.
There is a lot of data, close to 300Gb a day therefore I can't lose a
minute of outage.

I am capturing daily reports and cutoff is at 8:00AM.

process > /phys/data/20090922/20090922.crac.out
2>/phys/data/20090922/20090922.crac.err.out

At 7:59AM I kill the process using cron and restart the process at
8:00AM everyday for 5 days using cron. I lose 1 min of simulation data
:-(.

Is there a clever way to have my process run or restart at 8:00AM
without cron and no interruption? Or is this the preferred way?
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