If you know one list contains the other entirely, and neither has its own repetitions, ‘sort first second | uniq -u’ oughta work just fine.
Martin Dellwo martin.dellwo@gmail.com On May 27, 2021, at 8:29 PM, Walt Mankowski via plug <plug@lists.phillylinux.org> wrote:
I usually end up doing this in Perl or Python. The diff solution isnice. If you're interested, I've attached a little Perl script I justwhipped up. It has the advantage of not requiring the lists to besorted.Then I wrote a Python version, too. :)WaltOn Thu, May 27, 2021 at 07:36:05PM -0400, Michael Lazin via plug wrote:Awesome, thanks! Comm got the job done in a pinch but I am going to try
diff tomorrow morning. Thanks again for your help.
Sincerely,
Michael Lazin
On Thu, May 27, 2021, 6:01 PM Carlos M. Fernández <aremmes@gmail.com> wrote:
This has worked for me before:
diff -Nau first second | grep '^+'
This assumes that first and second are sorted.
On Thu, May 27, 2021, 17:37 Michael Lazin via plug <
plug@lists.phillylinux.org> wrote:
I used the sort command to make two lists. One list has everything on
the first list and more. They are already alphabetically sorted. I want
to know what is on the second list that is not on the first list. I am
trying to use diff but perhaps there is a better way. I tried awk and an
ugly egrep and now I am giving up and asking for help. Thanks for your
time.
Sincerely,
Michael Lazin
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