Quick easy question

[James <itjayw@yahoo.com>]

Here is a snippet of what I am trying to do

for ($i = 1; $i <= 6; $i++) {
   printf("$some_var$i");
   printf("$some$i_var");
}

I can't seem to be to have the $i resovle to a number
from the for loop.  NOTE: I do need to have the
underscore in the variable name.  Actually here is the
real printf code:

printf ("%-15s          %-15s          %-30s\n",
$DCS_DB{"$i"}, $DB{"$i"}_NM, $DB{"$i"}_DIR);

The above line is on one line despite how it looks in
this email.

Thanks in advance,
James
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