Re: [PLUG] python, lambda, map

[Dan Widyono <dan@widyono.net>]

On Sun, Oct 17, 2004 at 07:52:27PM -0400, Jeff Abrahamson wrote:
>     >>> def foo(x):
>     ...     return [x,x+1]
>     ...
>     >>> foo(3)
>     [3, 4]
>     >>> foo(3).extend(foo(5))
>     >>> L=foo(3).extend(foo(5))
>     >>> L
>     >>>

So, I'm not answering your map question.  However, I noticed that I got the
same results as your interactive session without expecting it.  I had to
L=foo(3), then L.extend(foo(5)).  Why?  Perhaps foo() is not returning a
modifiable object?  Can someone answer that?

I have a suspicion that fixing that issue will help you do the mapping you
want, the way you wanted to, Jeff.

In fact, with lists in general:

>>> b=[1,2,3]
>>> b
[1, 2, 3]
>>> b.append(7)
>>> b
[1, 2, 3, 7]
>>> [1,2,3]
[1, 2, 3]
>>> [1,2,3].append(7)
>>>

So I suppose it's a problem of incorrectly applying a method to an anonymous
type instance.

Dan W.

-- 
-- Daniel Widyono             --
-- www.widyono.net            --
-- www.cis.upenn.edu/~widyono --
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