Re: [PLUG] bash, double for

["Michael C. Toren" <mct@toren.net>]

On Thu, May 19, 2005 at 02:04:31PM -0400, Dan Crosta wrote:
>    n=`echo "$n + 1" | bc`

..

> There's also probably a better way to increment $n, but this is the 
> pattern I found first, so I use it.

You can use bash's $((..)) arithmetic substitution.  For example:

	echo $((n++))

or:

	n=$((n+1))

Not to be confused with bash's $(..) command substitution.

-mct

-- 
perl -e'$u="\4\5\6";sub H{8*($_[1]%79)+($_[0]%8)}sub G{vec$u,H(@_),1}sub S{vec
($n,H(@_),1)=$_[2]}$_=q^{P`clear`;for$iX){PG($iY)?"O":" "forX8);P"\n"}for$iX){
forX8){$c=scalar grep{G@$_}[$i-1Y-1Z-1YZ-1Y+1ZY-1ZY+1Z+1Y-1Z+1YZ+1Y+1];S$iY,G(
$iY)?$c=~/[23]/?1:0:$c==3?1:0}}$u=$n;select$M,$C,$T,.2;redo}^;s/Z/],[\$i/g;s/Y
/,\$_/xg;s/X/(0..7/g;s/P/print+/g;eval' #     Michael C. Toren <mct@toren.net>

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