[PLUG] floor/ceil in bash?

[Jason Stelzer <jason.stelzer@gmail.com>]

The details are boring and irritating, but I'm looking to get the ceil
for something in bash. Here's how I'm brute forcing it.

# This holds the value for the getCeil function
_MY_CEIL=""
# By default, bash is giving me back the floor for arithmatic. I want
the ceil.
# this implements this.
getCeil(){
    MAX=$1
    DIVISOR=$2
    X=$((${MAX}/${DIVISOR}))
    while [ $(($X * $DIVISOR)) -lt ${MAX} ] ; do
        X=$(($X + 1));
    done
    _MY_CEIL=${X};
}


Is there an easier way? And yeah, I know that using _MY_CEIL as a
bucket is kind of weird. Either way the code looks odd to me.

getCeil X Y
MY_VAR=${_MY_CEIL}

vs

MY_VAR=""
getCeil X Y ${MY_VAR}


-- 
J.
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