Re: [PLUG] "find" command troubles

[Walt Mankowski <waltman@pobox.com>]

On Tue, Apr 15, 2014 at 03:33:57PM -0400, JP Vossen wrote:
> On 04/15/2014 02:52 PM, brent timothy saner wrote:
> [...]
> >You can leave off the "-exec ls" part if you just want a list. :)
> >(you can also do -exec ls -l '{}' \; to repeat your two steps into one)
> [...]
> >find /mnt/backup/ -type f -mtime "+3" [-exec ls -l '{}' \;]
> >
> >The stuff in [] is optional, of course. (leave out the [] if you
> >actually want to include it)
> 
> Depending on your goal you may want to avoid using -exec if you can, since
> IIRC it will basically spawn a sub-shell per iteration.  That can quickly
> become a lot of overhead if you 'find' a lot of files.  OTOH, that can also
> be exactly what you need if you need to process them one at a time or
> something.  YMMV.
> 
> If all you want is 'ls -l' sort of output, look at the find "-ls" option,
> which is not the same format, but...  If you require either 'ls -l' or some
> other specific format, look at 'find ... -printf' and build your own.  Like:
> 
> # "CCYY-MM-DD HH:MM {tab} size {tab} path" sorted by path:
> find . -type f -printf '%TY-%Tm-%Td %TH:%TM\t%s\t%p\n' \
>  | sort -t'	' -k3,3

You could also avoid that -exec part by using xargs(1) with something
like this:

find /mnt/backup/ -type f -mtime "+3" | xargs ls -l

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