Re: [PLUG] Finding a /etc/group entry containing a user list

[JP Vossen <jp@jpsdomain.org>]

On 11/12/2011 02:30 PM, David Coulson wrote:
> Just run 'id' against each username and parse out the output. Remember
> /etc/group is typically just for supplemental groups - The user's
> primary group is usually only in /etc/passwd.

Since this is a Linux system, the primary group is the same as the user 
name, so that's no help.

I'd forgotten about the 'id' command, thanks for the reminder.  But I'm 
not sure I see how that helps me; it seems like I'd still need to parse 
stuff into some kind of data structure so I can get my answer.

Maybe I need an example.

If I have user01 to user10 (decimal, not binary :), and group01 to 
group40, I want to know that, say, group15 contains 8 out of 10 of my 
users, so if I can add user09 and user10 to group15, everyone will have 
the right perms once I chgrp the dir tree.

Of course, the flip side is that other users in group15 will have perms 
they don't need.  I don't really care too much for this purpose, but 
usually that would matter.  So maybe this question is less useful than I 
thought at first and yet-another-group really is the best answer.

Thanks,
JP
----------------------------|:::======|-------------------------------
JP Vossen, CISSP            |:::======|      http://bashcookbook.com/
My Account, My Opinions     |=========|      http://www.jpsdomain.org/
----------------------------|=========|-------------------------------
"Microsoft Tax" = the additional hardware & yearly fees for the add-on
software required to protect Windows from its own poorly designed and
implemented self, while the overhead incidentally flattens Moore's Law.
___________________________________________________________________________
Philadelphia Linux Users Group         --        http://www.phillylinux.org
Announcements - http://lists.phillylinux.org/mailman/listinfo/plug-announce
General Discussion  --   http://lists.phillylinux.org/mailman/listinfo/plug