Austin Murphy on 29 Sep 2010 14:08:59 -0700


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Re: [PLUG] Uncompressing vmlinuz to vmlinuz 2.6.33 kernel

  • From: Austin Murphy <austin.murphy@gmail.com>
  • To: "Philadelphia Linux User's Group Discussion List" <plug@lists.phillylinux.org>
  • Subject: Re: [PLUG] Uncompressing vmlinuz to vmlinuz 2.6.33 kernel
  • Date: Wed, 29 Sep 2010 17:08:53 -0400
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The compressed kernel probably loads faster.  Decompression in RAM is
typically much faster than BIOS I/O.

Austin

On Wed, Sep 29, 2010 at 1:39 PM, Edmond Rodriguez
<erodrig97.list@gmail.com> wrote:
> I guess this may have something to do with my previous query.   On or after,
> 2.6.30 , compression method changes.
>
> http://en.wikipedia.org/wiki/Vmlinux#Compression
>
>
> On Wed, Sep 29, 2010 at 11:02 AM, Edmond Rodriguez
> <erodrig97.list@gmail.com> wrote:
>>
>> I wished to try, purely by experimentation and some googling, to create a
>> vmlinux from my vmlinuz, so as to speed up the initial linux loading.  I am
>> not sure what can be gained, but for waking up from hibernation, I thought
>> it might be useful to cut a few seconds, if at all possible.   Any comments?
>>
>> I keep seeing from Google searches,  that I can look for the following hex
>> in vmlinuz and then decompress what follows using the following command,
>> plus some other io to extract the compressed portion of vmlinuz.
>>
>> od -A d -t x1 vmlinuz | grep '1f 8b 08'
>>
>> But I can't find that signature in my vmlinuz.
>>
>> Has that signature  changed or am I off track?
>>
>> Thanks,
>>
>> Edmond Rodriguez
>>
>
>
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