Re: [PLUG] Finding a /etc/group entry containing a user list

[bergman@merctech.com]

In the message dated: Sun, 13 Nov 2011 14:10:49 +0100,
The pithy ruminations from sean finney on 
<Re: [PLUG] Finding a /etc/group entry containing a user list> were:
=> On Sat, Nov 12, 2011 at 02:54:13PM -0500, JP Vossen wrote:
=> > But the original point is, I don't know what group to use.  I'm
=> > looking for the group that already contains the most members of my
=> > list, so that a) I don't need to create a new group and b) I need to
=> > add the fewest users to that group to that it contains everyone from
=> > my list.
=> 
=> something like this?
=> 
=> for group in `groups $users | cut -d: -f2-`; do
=> 	echo $group
=> done | sort | uniq -c | sort -n

Nice... or slightly more compact:

   	groups $users | cut -d: -f2-|tr " " "\012" |sort | uniq -c | sort -nr

I haven't had coffee yet this morning, so I'm not ready to think in 'awk', but
I'm sure the the process could be reduced to:

	groups $users | awk '{some hideous expression}'


It's like playing "Name That Tune" with command pipelines...can a process be
done with fewer fork()s?

Mark

=> 
=> 
=> :)
=> 
=> 	sean
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